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`        Length of a minute hand of a clock is 4.5cm. find the avg velocity (in cm/s) of the tip of minute`s hand between:I) 6 AM to 6:30AM II) 6AM to 6:30 PM`
8 months ago

Arun
13797 Points
```							Dear Preeti Speed of hour hand=0.5 degrees per minute.Speed of minutes hand=6 degrees per minuteangular distance moved by the minute hand between 6.00 Am to 6.30 Am=30 (6 degrees ) =180 degreesaverage angular velocity in this period is π/1800 rad/sso, angular velocity of the tip of minute hand will be4.5 x π/1800=0.0025πcm/ssimilarly for the second part the minute hand will cover( 6 degrees)(750)=4500 degreesAngular velocity in this period is25π/750x60=π/1800 rad/sAverage velocity of the tip of minute hand will be4.5 x π/1800=0.0025πcm/s
```
8 months ago
Biswajit
13 Points
```							There minute hand is of length 4.5cm ,but for displacement we only need initial and final point,so minute hand tip is on 12 at 6am and then on 6 at 6.30 am so total displacement of its tip is diameter of clock I.e 2*4.5=9cm ,avg velocity is 9/(30*60) cm/s=5*10^-3cm/s.2)that way you find between 6am to 6.30 pm I.e 9/(12.5*3600)=2*10^-4cm/s.
```
2 months ago
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