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Grade: 11
        Length of a minute hand of a clock is 4.5cm. find the avg velocity (in cm/s) of the tip of minute`s hand between:I) 6 AM to 6:30AM II) 6AM to 6:30 PM
8 months ago

Answers : (2)

Arun
13797 Points
							
Dear Preeti
 
Speed of hour hand=0.5 degrees per minute.
Speed of minutes hand=6 degrees per minute
angular distance moved by the minute hand between 

6.00 Am to 6.30 Am=30 (6 degrees ) =180 degrees
average angular velocity in this period is 
π/1800 rad/s
so, angular velocity of the tip of minute hand will be
4.5 x π/1800
=0.0025πcm/s
similarly for the second part the minute hand will cover( 6 

degrees)(750)=4500 degrees
Angular velocity in this period is
25π/750x60=π/1800 rad/s
Average velocity of the tip of minute hand will be
4.5 x π/1800=0.0025πcm/s
8 months ago
Biswajit
13 Points
							
There minute hand is of length 4.5cm ,but for displacement we only need initial and final point,so minute hand tip is on 12 at 6am and then on 6 at 6.30 am so total displacement of its tip is diameter of clock I.e 2*4.5=9cm ,avg velocity is 9/(30*60) cm/s=5*10^-3cm/s.
2)that way you find between 6am to 6.30 pm I.e 9/(12.5*3600)=2*10^-4cm/s.
2 months ago
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