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Grade: 11
        
kindly ans..que.28.
...we need to find theta....answer fast
2 months ago

Answers : (1)

Aditya Gupta
1690 Points
							
For projectile motion,
time of flight
T= 2usinθ / g
On squaring both sides,
T^2 = 4u^2 sin^2θ / g^2
or gT^2 = 4 u^2 sin^2 θ/ g--------(i)
and 
horizontal range
R = u^2sin2θ /g = 2u^2sinθcos θ/g--------(ii)
Dividing (i) by (ii),we get
 gT^2/R=2tanθ or gT^2=2R.tanθ
so, θ= tan^-1(gT^2/2R)
option 1
kindly approve :=)
2 months ago
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