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Grade: 12

                        

In the non-relativistic regime, if the momentum is increased by 100%, the percentage increase in kinetic energy is?

2 years ago

Answers : (1)

Arun
24742 Points
							
Dear Palakshi
 

Let the momentum of the particle be p ,

p = m*v.

where m is the mass of the particle and v is the velocity of the particle.

Now , Kinetic Energy = 1/2 * ( m * v^2 ).

K.E. = 1/2 * ( m^2 *v^2 )/m.

K.E. = 1/2 * ( p^2 )/m.

Now the mass of an object is constant. So the change in momentum is caused by change in velocity .

The momentum is increased by 100 % .

Therefore , the new momentum would be 2*p .

And the new K.E. will be

K.E. = 1/2 * ( 4 * p^2 ) / m. i.e., 4 times the old kinetic energy.

So, the percentage increase in kinetic energy will be 300 % .

 

Regards

Arun (askIITians forum expert)

2 years ago
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