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Give relation between current density and conductance?

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3 years ago

Arun
25768 Points
```							According to Ohm's law, the potential difference between ends of a conductor is directly proportional to the current, that isV α IOr      V=IR                                             (2)Where  R is resistance (that is obstruction offered to flow of changes)Also, when a current I flows in a uniform cross-section area normally to it, thenI=∫J.ds= ∫JdS cos 00=J∫dSI=JA          (3)     (where ∫dS = A)Also, resistance                                            R= ρl/A                                                 (4)Equation (3) can also be written asR=l/σA                                             (5)Where σ=1/ ρ is conductivitySubstituting equations (3) and (5) in equation (2) we getV=JA*l/σAV=Jl/σOr      J=σV/l                                       (6)But electric field intensity E=V/lBy putting above value of E in equation (6),we getJ= σ E
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3 years ago
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