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Grade: 11
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Find the coordinates of the centre of the circle inscribed in a triangle whose angular points are (-36,7),(20,7) and (0,-8)?Can you please solve this problem.

```
3 years ago

## Answers : (1)

Arun
24738 Points
```							The vertices of the triangle are A (-36,7) ,B (20,7) and C (0,-8)a = BC = √(0-20)² + (-8-7)²          =  √(-20)² + (-15)²          =  √400+225          =  √625          =  √25 x 25          =  25  b = CA = √(36-0))² + (7-(-8))²          =  √(36)² + (7+8)²          =  √1296 + 15²          =  √1296+225          =  √1521          =  √39 x 39          =  39 c = AB = √(20-(-36))² + (7-7)²          =  √(20+36)² + (0)²          =  √56²          =   √56 x 56          =  56Incentre I of the triangle is[(ax₁ + bx₂ + cx₃)/(a+b+c),(ay₁ + by₂ + cy₃)/(a+b+c)]      x₁ = -36 y₁ = 7 x₂ = 20 y₂ = 7  x₃ = 0 y₃ = -8       a = 25 b = 39  c = 56= [25(-36)+39(20)+56(0)/(25+39+56),25(7)+39(7)+56(-8)/(25+39+56)]  = [(-900+780+0)/(120),(175+273-448/(120)]= [(-120)/120,(448-448)/120]= (-1,0) So the incentre is (-1,0)
```
3 years ago
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