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Consider a cube of material of sides 1 cm with a resistance of 0.003 O between its opposite faces. What is the resistance if the same volume of the material is drawn into a length of 50cm with a uniform cross – section?
For 1 cm cube,Resistance is=>R = pl/A0.003 = p*1/(1*1)..............(1)For 50 cm cube,R’ = p*50/(50*50)....................(2)Dividing both the eqns. we get,R’ = 0.003/50 => 0.6 x 10^-4 ohm.
R = pl/A0.003 = p*1 cm/(V)0.003= p/(V)..............(1)For 50 cm cube,for same volume of the material divide volume(v) by 50R’ = p*50/(v/50)R’ = p*2500/(v)....................(2)solving (1) and (2)we get R'=7.5 ohm
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