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`        Can anyone solve this in the attachment. Please solve this question with proper description.`
one year ago

Arun
22998 Points
```							Dear student Use PMIn = 1,  we find that it is true.now assume that it is true for n = khence 4k + 15k – 1 = 9 Q now prove it for n = k+1 hence4k+1 + 15(k+1) – 14 * 4k + 15k + 15 – 14 * 4k + 15k +45 k+ 15 – 19 – 1 – 45k + 194 ( 4k + 15k -1) – (45k -18) 4 ( 4k + 15k -1) – 9*(5k – 2) Hence we see that the whole term is also divisible by 9 RegardsArun (askIITians forum expert)
```
one year ago
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