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`        Add vectors A ⃗,B ⃗  and C ⃗ each having magnitude of 100 unit and inclined to the X-axis at angles 45°, 135° and 315° respectively. `
5 years ago

Kevin Nash
332 Points
```							Sol.  x component of A ⃗ = 100 cos 45° = 100 / √2 unit
x component of B ⃗ = 100 cos 135° = 100 / √2
x component of C ⃗ = 100 cos 315° 100 / √2
Resultant x component = 100 / √2 – 100 / √2 + 100/ √2 = 100 √2
Y component of A ⃗ = 100 sin 45° = 100 / √2 unit
Y component of B ⃗ = 100 sin 135° = 100 / √2
Y component of C ⃗ = 100 sin 315° = 100 / √2
Resultant y component = 100 / √2 + 100 / √2 + 100 / √2 – 100 / √2 = 100 / √2
Resultant = 100

Tan α (y component )/(x component ) = 1
⇒ α = tan-1 (1) = 45°
The resultant is 100 unit at 45° with x-axis.

```
5 years ago
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