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A thin uniform, circular ring is rolling down an inclined plane of inclination 30° without slipping. Its linear acceleration along the inclined plane will be (a) g/2 (b) g/3 (c) g/4 (d) 2g/3

saurabh kumar , 12 Years ago
Grade 12
anser 1 Answers
Rs
a= gsin0 / (1+ mr^2)
 = g*(1/2)/(1+1) { i= mr^2} for ring
 = 9.8/2/2
=2.45 ans..............................................................................................................
Last Activity: 8 Years ago
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