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Grade 11General Physics

A tank is filled with water to a height of 12.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4 cm. What is the refractive index of water? If water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the microscope have to be moved to focus on the needle again?

Jayant Kumar

12 Years agoGrade 11

1 Answer

Vikas TU

6 Years ago

Apparent depth = real depth / refractive index

or

9.4 = 12.5 / μ

μ = 12.5 /9.4

μ = 1.33.

Now for the other part.

Apparent depth h' = 12.5 / μ'

h' = 12.5 /1.63

h' = 7.67

Previously apparent depth was 9.4 cm

Hence Microscope have to be moved by

= (9.4 - 7.67 )

= 1.73 cm.

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