A stone falls freely under gravity. It covers distances div, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between div, h2 and h3 is - (1) div = 2h2 = 3h3 (2) div = 5 h 3 h2 3 = (3) h2 = 3div and h3 = 3h2 (4) div = h2 = h3

(2)

Distance covered in first 5 sec. h1 = 0 + 2 1 a(5)2 h1 = 2 25a …(1) distance covered in first 10 sec S2 = 0 + 2 100a a(10) 2 1 2 = So distance covered in second 5 sec. h2 = S2 – h1 = 2 75a 2 25a 2 100a − = …(2) distance covered in first 15 sec. S3 = 0 + 2 225a a(15) 2 1 2 = so distance covered in last 5 sec. h3 = S3 – S2 = 2 125a 2 100a 2 225a − = ...(3) using (1), (2) and (3) equation. 2 125a h 2 75a h 2 25a h1 2 3 = = h1 = 5 h 3 h2 3 =

 

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