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Grade 9General Physics

A sample of metal weighs 210 g in air , 180 g in water and 120 g i an unknown liquid .then what will be density of that metal?

Profile image of Vaishnavi
10 Years agoGrade 9
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6 Answers

Profile image of surudhi
10 Years ago
The relative density of a metal = Weight of the metal in air / Loss in weight of metal in water = 210/(210-180) = 210/30 = 7.
Profile image of anonymous
9 Years ago
relative density = (weight of body in air -weight of body in liquid)/(weight of the body in air – weight of body in water)
weight of the body in air  =210g
weight of body in water = 180g
weight of body in liquid = 120g
 
(210-120) / (210-180) = 3
 
relative density = 3
Profile image of Jdlsjdfhj
9 Years ago
Metal=210/(210-180)= 7
In the Same way
Relative density of liquid=(210-120)/(210-180)=90/30=3
Ans) 7,3
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Profile image of Nitish
8 Years ago
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7 Years ago
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Profile image of Yash Chourasiya
6 Years ago
Dear Student

Relative density of metal = wieght in air / Change in weight of water
= (210) / (210 – 180)
Denstiy of metal = 7 g/cm2

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya