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A sample of metal weighs 210 g in air , 180 g in water and 120 g i an unknown liquid .then what will be density of that metal?

A sample of metal weighs 210 g in air , 180 g in water and 120 g i an unknown liquid .then what will be density of that metal?

Grade:9

6 Answers

surudhi
22 Points
8 years ago
The relative density of a metal = Weight of the metal in air / Loss in weight of metal in water = 210/(210-180) = 210/30 = 7.
anonymous
11 Points
7 years ago
relative density = (weight of body in air -weight of body in liquid)/(weight of the body in air – weight of body in water)
weight of the body in air  =210g
weight of body in water = 180g
weight of body in liquid = 120g
 
(210-120) / (210-180) = 3
 
relative density = 3
Jdlsjdfhj
23 Points
7 years ago
Metal=210/(210-180)= 7
In the Same way
Relative density of liquid=(210-120)/(210-180)=90/30=3
Ans) 7,3
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Nitish
19 Points
6 years ago
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Shifts
13 Points
5 years ago
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Yash Chourasiya
askIITians Faculty 256 Points
3 years ago
Dear Student

Relative density of metal = wieght in air / Change in weight of water
= (210) / (210 – 180)
Denstiy of metal = 7 g/cm2

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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