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A particle moving with acceleration 6 m/s 2 along x -axis covers 30 m in 5 th second. The distance covered by it in 4 th second is
A particle moving with acceleration 6 m/s2 along x-axis covers 30 m in 5th second. The distance covered by it in 4th second is

```
3 years ago

## Answers : (1)

Arun
25768 Points
```							As we know that distance covered in nth secondSn = u +(1/2) * f* (2n-1)Hence30 = u + (6/2) * (10-1)u = 30 -27 = 3 m/sec Hence distance covered in 4th secondS4 = 3 + (1/2)* 6* (9-1) = 3 + 24= 27 metres
```
3 years ago
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