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Grade: 12th pass

                        

A particle is moving on a circular on circular path with constant speed v. What is the change in its velocity after describing an angle of 60

2 years ago

Answers : (1)

Arun
25211 Points
							
Dear student
 
Since the particle has moved by an angle of 60o, if we join the initial and final positions of the particles with the center, the figure so formed will be an equilateral triangle. Since all the sides of an equilateral triangle are equal, the displacement would be equal to the radius of the circle.
 
Average velocity of the particle is = total displacent/time
Let the radius of the circle be R
Displacement = R
Now,
total time taken by the particle to complete 1 rotation i.e to cover 360o⇒T=2πRv
So, time taken to cover 60o⇒T1=16T
T1=πR3v
So, average velocity =RπRv
=vπ
 
 
Regards
Arun
2 years ago
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