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A particle is moving on a circular on circular path with constant speed v. What is the change in its velocity after describing an angle of 60
Dear student Since the particle has moved by an angle of 60o, if we join the initial and final positions of the particles with the center, the figure so formed will be an equilateral triangle. Since all the sides of an equilateral triangle are equal, the displacement would be equal to the radius of the circle. Average velocity of the particle is = total displacent/timeLet the radius of the circle be RDisplacement = RNow,total time taken by the particle to complete 1 rotation i.e to cover 360o⇒T=2πRvSo, time taken to cover 60o⇒T1=16TT1=πR3vSo, average velocity =RπRv=vπ RegardsArun
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