A man throws a stone in upward vertical direction from ground and reach Max height H. During ascent stone travels a distance H/5 in the last second. Then H is equal to :?

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Saurabh Koranglekar · Answer

Dear student s(t) &ndash; s(t-1) = u(t-(t-1)) + 0.5g ( t^2 &ndash; (t-1)^2 ) find t and substitute in v^2 = u^2 + 2gS Regards

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A man throws a stone in upward vertical direction from ground and reach Max height H. During ascent stone travels a distance H/5 in the last second. Then H is equal to :?

A man throws a stone in upward vertical direction from ground and reach Max height H. During ascent stone travels a distance H/5 in the last second. Then H is equal to :?

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A man throws a stone in upward vertical direction from ground and reach Max height H. During ascent stone travels a distance H/5 in the last second. Then H is equal to :?

A man throws a stone in upward vertical direction from ground and reach Max height H. During ascent stone travels a distance H/5 in the last second. Then H is equal to :?

1 Answers

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