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Grade: 10
        A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?
4 years ago

Answers : (2)

Jitender Pal
askIITians Faculty
365 Points
							(b) AF = AB – BF = AB – DE = 50 – 20 = 30 m
His displacement is AD
AD = √(AF^2-DF^2 )   = √(〖30〗^2+〖40〗^2 ) = 50m
In ∆AED tan θ = DE/AE = 30/40 = ¾
⇒ θ = tan-1 (3/4)
His displacement from his house to the field is 50 m,
tan-1 (3/4) north to east. 

						
4 years ago
Gaurav Kumar
11 Points
							Gjhgufyhduhfhu8tt7665ufyifgjvxyiusjrhrirt jghrurh4ui8rhrvdi3j4bejei2u3ie ki yudhfd du gaurav l kumar krib vyngy
						
7 months ago
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