Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field. (a) What distance he has to walk to reach the field? (b) What is his displacement from his house to the field?`
5 years ago

Jitender Pal
365 Points
```							(b) AF = AB – BF = AB – DE = 50 – 20 = 30 m
AD = √(AF^2-DF^2 )   = √(〖30〗^2+〖40〗^2 ) = 50m
In ∆AED tan θ = DE/AE = 30/40 = ¾
⇒ θ = tan-1 (3/4)
His displacement from his house to the field is 50 m,
tan-1 (3/4) north to east.

```
5 years ago
Gaurav Kumar
11 Points
```							Gjhgufyhduhfhu8tt7665ufyifgjvxyiusjrhrirt jghrurh4ui8rhrvdi3j4bejei2u3ie ki yudhfd du gaurav l kumar krib vyngy
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions