a car starting from rest has a speed of 30km/h at any one instant. two seconds later, its speed is 36km/hr and 2sec after that, it is 42km/hr, its accelaration in m/s^2 is?

Question

Vikas TU · Answer

For fiest instant, v = u + at 30 = 0 + a*t............(1) After 2 seconds that is after (t+2) 36 = 30 + a(t+2) or 6 = at + 2a..........(2) solving both eqns we get, 2a = -24 a = -12 m/s^2. which could not be possible as it has travelled further more after these 2 seconds but the accln is deccelation. Hence not possible.

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a car starting from rest has a speed of 30km/h at any one instant. two seconds later, its speed is 36km/hr and 2sec after that, it is 42km/hr, its accelaration in m/s^2 is?

a car starting from rest has a speed of 30km/h at any one instant. two seconds later, its speed is 36km/hr and 2sec after that, it is 42km/hr, its accelaration in m/s^2 is?

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a car starting from rest has a speed of 30km/h at any one instant. two seconds later, its speed is 36km/hr and 2sec after that, it is 42km/hr, its accelaration in m/s^2 is?

a car starting from rest has a speed of 30km/h at any one instant. two seconds later, its speed is 36km/hr and 2sec after that, it is 42km/hr, its accelaration in m/s^2 is?

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