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A car is travelling on straight level road with a uniform speed of 60kmph it is followed by another car B which is moving with speed of 70kmph when the distance between them is 2.5km the car Back is given a deceleration of 20km/h2 after what distance of time B will catch up with A
s2 = ut + ½*a*t2 = 70t + ½*(-20)*t2 = 70t -10t2s1 = 60ts2 – s1 = 2.570t – 10t2 -60t = 2.510t2 -10t + 2.5 = 0so t = ½ hputting this in s2s2 = 32.5kmHope it clears.
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