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A bullet of mass m moving vertically upwards with a velocity u hits the hanging block of mass m and gets embedded in it.The height through which the block rises after the collision, assume sufficient space above the block
conserve the energy,0.5mu^2 + 0 = 0.5(m + m)v^2 + 2mghu^2/2 = v^2 + 2gh.........(1)momentum conservation,mu = 2mvoru = 2v.........(2)solve both eqns. and get h value.
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