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Grade: 11
`        A body rolled on a surface with a speed of 10m/sec comes to rest after covering a distance of 50m.Find the coefficent of friction.g=10m/sec2`
2 years ago

## Answers : (1)

Arun
23742 Points
```							Dear nandini v^2 - u^2 = 2as 0-100=2*a*50 -100/100=a a=-1 m/s^2 Negative sign shows retardation. let n be the coeff. of friction, n*mg=m*a n=a/g n=1/10n=0.1 RegardsArun(askIITians forum expert)
```
2 years ago
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