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A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ? A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ?
Range for earth R = u² sin2/g(earth)Now At moonRange R' = u² sin2/g(moon)But g(moon) = g(earth)/6HenceR' = 6 u² sin2/gR' = 6R
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