A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ?

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Arun · Answer

Range for earth R = u² sin2 /g(earth) Now At moon Range R' = u² sin2 /g(moon) But g(moon) = g(earth)/6 Hence R' = 6 u² sin2 /g R' = 6R

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A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ?

A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ?

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A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ?

A body projected with velocity u at projection angle β has horizontal range R . For the same velocity and projection angle, its range on the moon surface will be (g moon=g earth/6) ?

1 Answers

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Other Related Questions on General Physics

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