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`        A body is pushed giving it an initial velocity of 5ms-1 and comes to rest after travelling 4.9m. Find the co efficient of friction? `
3 months ago

Arun
23330 Points
```							from v2=u2+2as 0=52+(-2a×4.9) a =2.55m/s2Now fk=ma. It is the only force acting in x direction.and normal reaction (R) =mgalso fk=u*R, u*=fk/Rputting values- u*=ma/mgu*=2.55/10coff of friction (u*) =0.25
```
3 months ago
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