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Grade: 11
        
A body falling from a vertical height of 10 m pierces through a distance of 1 m in sand. it faces an average retardation equal to (g= acceleration due to gravity):
1)g2)9g
3)100g
4)1000g
5 years ago

Answers : (2)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							Hi
v^2=2gs=>200
again
v^2=2as=>a=200/2=100m/s^2
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
5 years ago
KAPIL MANDAL
132 Points
							
Thank you sir for this answer. Thank you very much.
4 years ago
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