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Grade: 12

                        

A bicycle wheel of radius 0.3m has a rim of mass 1 kg and 50 spokes , each of mass 0.01kg. what is its moment of inertia about its axis.

4 years ago

Answers : (2)

Ankit Jaiswal
165 Points
							
hi pulkit 
            i think this might help u 
as we know that the moment of inertia of ring about the axis passing through its center and perpendicucal to the plane is MR2 and that of rod of length L about an aixs passing through its end and perpenducular to the length of rod is ML2/3
so by using these two bodies we can find the moment of inertia of this wheel ( considering rim as ring and spokes as rods )
we get
moment of inertia of rim as MR2 = 1*0.3*0.3 = 0.09 kg m2
and the moment of inertia of all spokes =50*ML2/3=50*0.01*0.3*0.3/3 =0.015 kg m2
so the total moment of inertia of the wheel about its axis is 0.09+0.015
= 0.105 kg m^{2}
4 years ago
Keshav Sharma
11 Points
							
WE MAY BE ABLE TO FIND THE MOMENT OF INERIA OF WHOLE OBJECT BY THE SUM OF MOMENT OF INERTIA OF THE RING AND THE SPOKES SEPERATELY:-
 
MOMENT OF INERTIA OF A RING =MR2= 1.00 X (0.3)2
                                                                                 = 0.09
 
MOMENT OF INERTIA OF THE SPOKES= MOMENT OF INERTIA OF A ROD WITH RADIUS 0.3 AND MASS 0.5(0.01 X 50)
                                                                   =MR2/3 = [0.5 X (0.3)2]/3
                                                                   = 0.015.
 
MOMENT OF INERTIA WHOLE BODY= 0.09+0.015 = 0.105KG-M
 
2 years ago
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