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A bicycle wheel of radius 0.3m has a rim of mass 1 kg and 50 spokes , each of mass 0.01kg. what is its moment of inertia about its axis.
A bicycle wheel of radius 0.3m has a rim of mass 1 kg and 50 spokes , each of mass 0.01kg. what is its moment of inertia about its axis.

```
4 years ago

Ankit Jaiswal
165 Points
```							hi pulkit             i think this might help u as we know that the moment of inertia of ring about the axis passing through its center and perpendicucal to the plane is MR2 and that of rod of length L about an aixs passing through its end and perpenducular to the length of rod is ML2/3so by using these two bodies we can find the moment of inertia of this wheel ( considering rim as ring and spokes as rods )we getmoment of inertia of rim as MR2 = 1*0.3*0.3 = 0.09 kg m2and the moment of inertia of all spokes =50*ML2/3=50*0.01*0.3*0.3/3 =0.015 kg m2so the total moment of inertia of the wheel about its axis is 0.09+0.015$= 0.105 kg m^{2}$
```
4 years ago
Keshav Sharma
11 Points
```							WE MAY BE ABLE TO FIND THE MOMENT OF INERIA OF WHOLE OBJECT BY THE SUM OF MOMENT OF INERTIA OF THE RING AND THE SPOKES SEPERATELY:- MOMENT OF INERTIA OF A RING =MR2= 1.00 X (0.3)2                                                                                 = 0.09 MOMENT OF INERTIA OF THE SPOKES= MOMENT OF INERTIA OF A ROD WITH RADIUS 0.3 AND MASS 0.5(0.01 X 50)                                                                   =MR2/3 = [0.5 X (0.3)2]/3                                                                   = 0.015. MOMENT OF INERTIA WHOLE BODY= 0.09+0.015 = 0.105KG-M
```
3 years ago
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