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`        A ball of relative density of .8 had fell in water from 2 metre. Find the depth of water `
one year ago

```							Speed of the ball V = sqrt (2 gh)= 6.32 m/sBuoyancy force by water try to stop the ball. Buoyancy force = weight of displaced water = (d V)gwhere d = density of waterV = volume of the ball  g = 10 m/s2deceleration of the body by buoyancy force, a = (dVg)/ mwhere m= d'Vd' = density of blocka = dVg/(d' V)= dg/d'=(d/d')*g=g/(0.8)= 10/0.8  (Given, d'/d = 0.8)= 12.5 m/s2 Net deceleration of ball,a' = a-g = 2.5 m/s2Final speed of ball v' = 0Use v' 2 = v2 + 2a's s= depth of ball in the water=> 40 = 0 + 2*2.5*s=> s = 8m
```
one year ago
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