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Speed of the ball
V = sqrt (2 gh)
= 6.32 m/s
Buoyancy force by water try to stop the ball.
Buoyancy force = weight of displaced water
= (d V)g
where d = density of water
V = volume of the ball
g = 10 m/s2
deceleration of the body by buoyancy force, a = (dVg)/ m
where m= d'V
d' = density of block
a = dVg/(d' V)
= dg/d'
=(d/d')*g
=g/(0.8)
= 10/0.8 (Given, d'/d = 0.8)
= 12.5 m/s2
Net deceleration of ball,a' = a-g = 2.5 m/s2
Final speed of ball v' = 0
Use v' 2 = v2 + 2a's
s= depth of ball in the water
=> 40 = 0 + 2*2.5*s
=> s = 8m
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