A ball is projected at an angle 45degrees with horizontal.It passes through a wall of height h at a horizontal distance d1 from the point of projection and strikes the ground at a horizontal distance d1+d2 from the point of projection ,prove h= 2 d1d2/d1+d2

Question

Vikas TU · Answer

in vertical direcn. eqns. h = usin45 * t – 0.5gt^2....................(1) in horizontal direcn. d1 = ucos45 * t......................(2) Also, again for second part distance apply same formulaes for same height h in vertical and d2 distance in horizontal direction. and solve the 4 eqns. and get the values.

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A ball is projected at an angle 45degrees with horizontal.It passes through a wall of height h at a horizontal distance d1 from the point of projection and strikes the ground at a horizontal distance d1+d2 from the point of projection ,prove h= 2 d1d2/d1+d2

A ball is projected at an angle 45degrees with horizontal.It passes through a wall of height h at a horizontal distance d1 from the point of projection and strikes the ground at a horizontal distance d1+d2 from the point of projection ,prove h= 2 d1d2/d1+d2

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