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A ball is projected at an angle 45degrees with horizontal.It passes through a wall of height h at a horizontal distance d1 from the point of projection and strikes the ground at a horizontal distance d1+d2 from the point of projection ,prove h= 2 d1d2/d1+d2
in vertical direcn. eqns.h = usin45 * t – 0.5gt^2....................(1)in horizontal direcn.d1 = ucos45 * t......................(2)Also,again for second part distance apply same formulaes for same height h in vertical and d2 distance in horizontal direction.and solve the 4 eqns. and get the values.
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