one second after projection a stone moves at an angke of 45degree with the horizantal.two seconds after projectioin it moves horizantly . its angel of projection in degree is ???

Dear jauneet

let angel of projection is Θ and initial velocity is U

so verticle velocy = UsinΘ

  horixontal velocity =UcosΘ

after 1 sec verticle velocity will be

 V = UsinΘ -g

 horizontal velocity will remain same

so tan45 =1 = [UsinΘ -g]/UcosΘ   .............1

after 2 sec verticle velocity will be zero

 0 = UsinΘ -2g

  g = UsinΘ /2

put this value in equation 1

 1 = [UsinΘ -UsinΘ /2 ]/UcosΘ

 1 = tanΘ /2

  tanΘ =2

 Θ =tan^-12

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