a calorimeter contains12 gm of ice and 100 gm of water at 0 degre c .The water equivalent of the calorimeter is 25 gm .if 5 gm of steam is passed at 100 degre c in the calorimeter,then calculate the temperature of the mixture

Question

Apoorva Arora · Answer

According to the law of conservation of heat.

Heat lost by the steam= Heat gained by ice and water.

To reach a common temperature, firstly the ice will melt, and heat required is:

$Q_{1}=m_{ice}\times L_{fusion}$

=4008 joules

Now,

$Q_{1}+ m_{water}(net)\times s_{water}\times (273-T)=m_{steam}\times s_{_{steam}}\times (T-373)$

Therefore,

T=8.6 degree Celsius (approx.)

Thanks and Regards

Apoorva Arora

IIT Roorkee

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a calorimeter contains12 gm of ice and 100 gm of water at 0 degre c .The water equivalent of the calorimeter is 25 gm .if 5 gm of steam is passed at 100 degre c in the calorimeter,then calculate the temperature of the mixture

a calorimeter contains12 gm of ice and 100 gm of water at 0 degre c .The water equivalent of the calorimeter is 25 gm .if 5 gm of steam is passed at 100 degre c in the calorimeter,then calculate the temperature of the mixture

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a calorimeter contains12 gm of ice and 100 gm of water at 0 degre c .The water equivalent of the calorimeter is 25 gm .if 5 gm of steam is passed at 100 degre c in the calorimeter,then calculate the temperature of the mixture

a calorimeter contains12 gm of ice and 100 gm of water at 0 degre c .The water equivalent of the calorimeter is 25 gm .if 5 gm of steam is passed at 100 degre c in the calorimeter,then calculate the temperature of the mixture

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