The dimensions of a/b in the equation P = (a-t^2)/bx where P is pressure, x is distance and t is time are
    (a)    M2LT–3
    (b)    MT–2
    (c)    ML3T–1
    (d)    LT–3

Question

The dimensions of a/b in the equation P = (a-t^2)/bx where P is pressure, x is distance and t is time are (a) M2LT&ndash;3 (b) MT&ndash;2 (c) ML3T&ndash;1 (d) LT&ndash;3

Simran Bhatia · Answer

(b) P = &THORN; Pbx = a &ndash; t 2 &reg; [Pbx] = [a] = [T 2 ] Or [b] = = [M &ndash;1 T 4 ] = [MT &ndash;2 ]

Swetank Gupta · Answer

[a]=[t 2 ]=T 2 [P]=T 2 /[bx] [b]=T 2 /[P][x]=T 2 /ML -1 T -2 L=M -1 T 4 a/b=T 2 /M -1 T 4 =MT -2 Thanks And Regards Swetank Gupta

Karan Kaushal · Answer

The ratio of power out put of engines of two helicopters when linear size of one helicopters is one fourth of linear size of other and all other parameters are same is.

Rishi Sharma · Answer

Dear Student, Please find below the solution to your problem. [a]=[t2]=T2 [P]=T2/[bx] [b]=T2/[P][x]=T2/ML-1T-2L=M-1T4 a/b=T2/M-1T4=MT-2 Thanks and Regards

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The dimensions of a/b in the equation P = (a-t^2)/bx where P is pressure, x is distance and t is time are (a) M2LT–3 (b) MT–2 (c) ML3T–1 (d) LT–3

The dimensions of a/b in the equation P = (a-t^2)/bx where P is pressure, x is distance and t is time are
    (a)    M2LT–3
    (b)    MT–2
    (c)    ML3T–1
    (d)    LT–3

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