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An elevator consists of the elevator cage M and counterweight m, driving mechanism C and cables and pulleys as shown.

M = 1000 Kg, m = 1400 kg

The elevator is accelerating upward at 2.30 m/s2.

1229_88601_Image~

Find (a) T1, (b) T2

and the force exerted by the driving mechanism C on the cable.

Navjyot Kalra , 11 Years ago
Grade 10
anser 1 Answers
Deepak Patra

Last Activity: 11 Years ago

From the free body diagrams

Ma = T1 – Mg                              ma = mg – T2

(a)    T1 = M (a + g)                    (b)    T2 = m(g – a)

= 12.1 kN                                  = 10.5 kN

761_88602_Image~ 1.jpg

Assume the cable is massless. Mass even though it is accelerating no net force acts on it.

This means T2 + C2 = T1

C2 = 1.6 kN towards the counter weight.

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