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A subway train starting from rest leaves a station with a constant acceleration. At the end of 7.98 s, it is moving at 15.2418 m/s. What is the train’s displacement in the ?rst 5.19498 s of motion? Answer in units of m
v=u + at
where u=0 (since it starts from rest)
from this,
a=(15.2418)/7.98
now use ,
s=ut+(1/2)at^2
where u=0
s=25.7m
hey,guy,is there two que.?
if there is 2 questions,,,
so,the first ans is 315.72m
HEY,FRIEND,,
IS THERE TWO QUE.?
IF,IT IS,,,,
SO,THE FIRST ANS WOULD BE 485.30m
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