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An electric bulb is rated 220 V and 100 W.When it is operated on 110 V, the powerconsumed will be :-

anshul gupta , 11 Years ago
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anser 3 Answers
Narayanarao laveti

Last Activity: 11 Years ago

power (watts) = current (amps) x potential difference (volts)

P=I*V

=>P1/P2=V1/V2

=>220 v/110v=100w/v2

=>v2=100/2

:. V2=50 v

rohit yadav

Last Activity: 11 Years ago

25 W

Roshan Mohanty

Last Activity: 11 Years ago

P=V*I
I will be same in both cases
so
P1=V1*I
P2=V2*I
Dividing both equations,
P1/P2=V1/V2
100/P2=220/110
P2=50 (Ans) 

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