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An electric bulb is rated 220 V and 100 W.
When it is operated on 110 V, the power
consumed will be :-
power (watts) = current (amps) x potential difference (volts)
P=I*V
=>P1/P2=V1/V2
=>220 v/110v=100w/v2
=>v2=100/2
:. V2=50 v
25 W
P=V*II will be same in both casessoP1=V1*IP2=V2*IDividing both equations,P1/P2=V1/V2100/P2=220/110P2=50 (Ans)
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