19 gm of water at 30 degree celcius and 5 gm of ice at -20 degree celcius are mixed find the final temperature

Question

Apoorva Arora · Answer

To come to a common temperature, First of all the ice will come to 0 degrees

heat=m*s*change in temp=2000 joules

then the ice will melt

heat=m*latent heat of fusion= 1670 joules

therefore now water at 0 degrees will gain heat and water at 30 degrees will lose heat. and according to the conservation of heat we can calculate the common temperature.

$2000+1670+.005\times s_{water}\times \Delta T_{1}=.019\times s_{water}\times \Delta T_{2}$

Thanks and Regards

Apoorva Arora

IIT Roorkee

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19 gm of water at 30 degree celcius and 5 gm of ice at -20 degree celcius are mixed find the final temperature

19 gm of water at 30 degree celcius and 5 gm of ice at -20 degree celcius are mixed find the final temperature

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19 gm of water at 30 degree celcius and 5 gm of ice at -20 degree celcius are mixed find the final temperature

19 gm of water at 30 degree celcius and 5 gm of ice at -20 degree celcius are mixed find the final temperature

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