An object floats in water such that 1/5 of its volume is above the surface of water. When the same object is made to float in sample of impure alcohol, the volume that remains outside the liquid is 1/20 of total volume . the relative density of the sample of alcohol will be

Question

Aman Bansal · Answer

Dear Sanjana,

f the fraction in water=alfa and the fraction in alcohol=beta
then RD of alcohol=1-alfa/1-beta=(1-1/5)/(1-1/20)=1

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An object floats in water such that 1/5 of its volume is above the surface of water. When the same object is made to float in sample of impure alcohol, the volume that remains outside the liquid is 1/20 of total volume . the relative density of the sample of alcohol will be

An object floats in water such that 1/5 of its volume is above the surface of water. When the same object is made to float in sample of impure alcohol, the volume that remains outside the liquid is 1/20 of total volume . the relative density of the sample of alcohol will be

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An object floats in water such that 1/5 of its volume is above the surface of water. When the same object is made to float in sample of impure alcohol, the volume that remains outside the liquid is 1/20 of total volume . the relative density of the sample of alcohol will be

An object floats in water such that 1/5 of its volume is above the surface of water. When the same object is made to float in sample of impure alcohol, the volume that remains outside the liquid is 1/20 of total volume . the relative density of the sample of alcohol will be

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