A container of mass 200kg rests on the back of an open truck.if the truck accelerates 1.5m/secondsquare.what is the minimum co-efficient of static friction between the container and the bed of the truck required to prevent the container from sliding off the back of the truck is?

Dear Likhhit,

Fsf = ma, Fsf = k * m * g.
k * m * g = m * a
k * g = a
k = a / g
k = 1.5 / 9.8 = 0.1531

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