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block is acted by spring of k.and weak friction force f.block pulled x from equilibrium and released.oscillates and finally comes to rest.find decrease in amplitude in each oscillation
by work energy theorem, 1/2 kx^2 =f{x+a}+1/2ka^2 x-a= 2f/k x-a is the decrease in the amplitudean dconstant for each cycle.
by work energy theorem,
1/2 kx^2 =f{x+a}+1/2ka^2
x-a= 2f/k
x-a is the decrease in the amplitudean dconstant for each cycle.
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