Flag General Physics> please solve...
question mark

a particle confined to motion along x axis moves with a constant accelaration fro x=2m to x=8m during the 2.5secs time interval. the velocity of particle at x=8m is 2.8m/s. what is the accelaration during this time interval?

goutham 1995 gumm , 13 Years ago
Grade 12
anser 1 Answers
Swapnil Saxena

Last Activity: 13 Years ago

Make use of Newtons 1, 3  equation

t=2.5, s=6, v=2.8

v= u+a(2.5) --(i)

v^2= u^2+2a(6)---(iii)

Using equation I and II we get (v+u )=24/5= 4.8

When v= 2.8 the the initial velocity of the particle is 2m/s

Usin i equation

Acceleartion is  0.8/2.5 = 8/25 = 0.32m/s^2

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments