Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 11
        A force F=(10i+5j)N acts on a body of mass 10gm.If the body is at origine at time t=0,then what would be its position at time t=5s?
10 years ago

Answers : (1)

Ramesh V
70 Points

F = 10i + 5j  

as F=ma where m=0.01kg

accl. of body(a) = 1000i+500j

equation of motion is : S = ut + 0.5at2 with starting at rest , u =0

position = (0.5*1000*25 i + 0.5*500*25 j )

            = (12500 i + 6250 j)


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult
to understand - post it here and we will get you the answer and detailed solution very quickly.We are all
IITians and here to help you in your IIT JEE preparation. All the best.

IIT Kgp - 05 batch

10 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details