Chetan Mandayam Nayakar
Last Activity: 14 Years ago
g=32ft/sec2,horizontal component of velocity is constant throughout the motion, and equal to (15*228)/√(2282+1712)=v1
initial vertical velocity component =v2=(15*171)/√(2282+1712),let time taken to hit ground be 't',171=(v2*t)+(g/2)t2,even though this is a quadratic equation, the choice of the correct root tc will be obvious. horizontal distance travelled= (v1*tc)