AskIITians Expert Hari Shankar IITD
Last Activity: 15 Years ago
Net resistance R = R1 + R2
(In a series combination, resistances get added)
Max error in measurement of R1 = 3 ohm.
Relative error = Max. error/Measured value
Therefore,
Relative error for R1 = 3/600 = 0.005
Max error in measurement of R2 = 6 ohm.
Relative error for R2 = 6/300 = 0.02
When two quantities are added, the respective errors involved also get added.
R = R1 + R2
Measured value of R = 600 + 300 = 900 ohms
Error in measuring R = 3 + 6 = 9 ohm
Relative Error in measurement of R = 9/900 = 0.01
Percentage error = Relative error * 100
or, Percentage error = 0.01* 100
or, Percentage error in measuring R = 1 %