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6 identical particles each of centre of mass m are arranged at the corners of a regular hexagon of side lenght l. if the mass of one of the particles is doubled the shift of the centre of mass is?

6 identical particles each of centre of mass m are arranged at the corners of a regular hexagon of side lenght l. if the mass of one of the particles is doubled the shift of the centre of mass is?

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3 Answers

Chetan Mandayam Nayakar
312 Points
12 years ago

before doubling, com is at centre of hexagon

after doubling shift =ml/7m=l/7

Markandeya Singh
18 Points
8 years ago
A detailed answer will be ,
take case as the com being a point mass and the doubled mass be another one.
now solve it with this idea
Markandeya Singh
18 Points
8 years ago
A detailed answer will be ,
take case as the com being a point mass and the doubled mass be another one.
now solve it with this idea

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