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6 identical particles each of centre of mass m are arranged at the corners of a regular hexagon of side lenght l. if the mass of one of the particles is doubled the shift of the centre of mass is?
before doubling, com is at centre of hexagon after doubling shift =ml/7m=l/7
before doubling, com is at centre of hexagon
after doubling shift =ml/7m=l/7
A detailed answer will be ,take case as the com being a point mass and the doubled mass be another one.now solve it with this idea
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