6 identical particles each of centre of mass m are arranged at the corners of a regular hexagon of side lenght l. if the mass of one of the particles is doubled the shift of the centre of mass is?

Question

Chetan Mandayam Nayakar · Answer

before doubling, com is at centre of hexagon after doubling shift =ml/7m=l/7

Markandeya Singh · Answer

A detailed answer will be , take case as the com being a point mass and the doubled mass be another one. now solve it with this idea

Markandeya Singh · Answer

A detailed answer will be , take case as the com being a point mass and the doubled mass be another one. now solve it with this idea

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6 identical particles each of centre of mass m are arranged at the corners of a regular hexagon of side lenght l. if the mass of one of the particles is doubled the shift of the centre of mass is?

6 identical particles each of centre of mass m are arranged at the corners of a regular hexagon of side lenght l. if the mass of one of the particles is doubled the shift of the centre of mass is?

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