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A small block slides without friction down an inclined starting form rest. Let S n be the distance travelled from time t = n-1 to t = n. Then S n /S n+1 is - (A) 2n-1/2n (B) 2n+1/2n+1 (C) 2n-1/2n+1 (D) 2n/2n+1

 A small block slides without friction down an inclined starting form rest. Let Sn be the distance travelled from time


t = n-1 to t = n. Then Sn/Sn+1 is -


(A)   2n-1/2n


(B)   2n+1/2n+1


(C)   2n-1/2n+1


(D)   2n/2n+1

Grade:11

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear aditya,

The correct answer is c)

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Sagar Singh

B.Tech IIT Delhi

Sukhendra Reddy Rompally B.Tech Mining Machinery Engg, ISM Dhanbad
93 Points
10 years ago
Hi Aditya! The distance travelled by a body during the nth second of its motion is given by Sn=u+a(n-0.5),where u is the initial velocity of the particle,and a is the uniform acceleration.This equation can be derived quite easily by calculating the distance travelled in first n sec and first n-1 sec and subtracting them.Here u=0,a=gsinx,where x is the angle of inclination.now substituting the values,we get the required ratio=(n-0.5)/(n+1 -0.5) = (2n-1)/(2n+1) ALL THE BEST PLZZ APPROVE MY ANSWER IF YOU LIKE IT

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