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# A small block slides without friction down an inclined starting form rest. Let Sn be the distance travelled from timet = n-1 to t = n. Then Sn/Sn+1 is -(A)   2n-1/2n(B)   2n+1/2n+1(C)   2n-1/2n+1(D)   2n/2n+1

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

The correct answer is c)

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Sagar Singh

B.Tech IIT Delhi

Sukhendra Reddy Rompally B.Tech Mining Machinery Engg, ISM Dhanbad
93 Points
10 years ago
Hi Aditya! The distance travelled by a body during the nth second of its motion is given by Sn=u+a(n-0.5),where u is the initial velocity of the particle,and a is the uniform acceleration.This equation can be derived quite easily by calculating the distance travelled in first n sec and first n-1 sec and subtracting them.Here u=0,a=gsinx,where x is the angle of inclination.now substituting the values,we get the required ratio=(n-0.5)/(n+1 -0.5) = (2n-1)/(2n+1) ALL THE BEST PLZZ APPROVE MY ANSWER IF YOU LIKE IT