A small block slides without friction down an inclined starting form rest. Let S_n be the distance travelled from time

t = n-1 to t = n. Then S_n/S_n+1 is -

(A) 2n-1/2n

(B) 2n+1/2n+1

(C) 2n-1/2n+1

(D) 2n/2n+1

Dear aditya,

The correct answer is c)

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Sagar Singh

B.Tech IIT Delhi

Hi Aditya! The distance travelled by a body during the nth second of its motion is given by Sn=u+a(n-0.5),where u is the initial velocity of the particle,and a is the uniform acceleration.This equation can be derived quite easily by calculating the distance travelled in first n sec and first n-1 sec and subtracting them.Here u=0,a=gsinx,where x is the angle of inclination.now substituting the values,we get the required ratio=(n-0.5)/(n+1 -0.5) = (2n-1)/(2n+1) ALL THE BEST PLZZ APPROVE MY ANSWER IF YOU LIKE IT