A straight rod of length L extends from x=0 to x=L. The linear mass density of rod varies with x co-ordinate is λ=a₀+b₀x². The gravitational force experienced by a point mass m at x=-a is...............

((please solve it for me))

Dear Pravesh,
F = Gm1*m2/d^2
dm1 = (ao + box^2) dx
m1 = ao * L + bo * L^3/3  this is mass of rod
m2 = m
here d = a + L/2
plug in all the values in formula.
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