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A straight rod of length L extends from x=0 to x=L. The linear mass density of rod varies with x co-ordinate is λ=a0+b0x2. The gravitational force experienced by a point mass m at x=-a is...............

((please solve it for me))

pravesh gupta , 14 Years ago
Grade 12
anser 2 Answers
Anil Pannikar AskiitiansExpert-IITB

Last Activity: 14 Years ago

Dear Pravesh,
F = Gm1*m2/d^2
dm1 = (ao + box^2) dx
m1 = ao * L + bo * L^3/3  this is mass of rod
m2 = m
here d = a + L/2
plug in all the values in formula.
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Anil Pannikar
IIT Bombay

Ajudiya Janvi

Last Activity: 8 Years ago

Two metallic sphere of mass M are suspended by two strings each of length L The distance between the upper ends of strings is L. The angle which the strings will make with the vertical due to mutual attraction of sphere is (if each mass horizontally moved by a distance of L/4 due to mutual attraction)

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