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A half ring of radius R has a charge of per unit length .The potential at the centre of the half ring is (Assuming potential at infinity is zero and ) Possible Answers Selected Possible Answer




A half ring of radius R has a charge of \lambda per unit length .The potential at the centre of the half ring is (Assuming potential at infinity is zero and k = \frac{1}{4\pi\epsilon_\circ})




Possible Answers























Selected Possible Answer


k \frac{\lambda}{R}




k \frac{\lambda}{\pi R}




k \frac{\pi \lambda}{R}




k \pi \lambda



Grade:12

1 Answers

Pranav
12 Points
3 years ago
THE TOTAL CHARGE ON THE WHOLE RING IS 
Lambda × the circumference of the ring =
Lambda× 2πR
 
IN CASE OF HALF RING THE CHARGE WILL BE
Lambda × 2πR ÷ 2 = 
Lambda × πR
 
WE KNOW, THE FORMULA FOR POTENTIAL AT A POINT i.e 
V= KQ÷ R
 
WE ALSO KNOW THAT 
Q= LAMBDA × L
(Here for half ring L is πR)
Q= Lambda × πR
 
THEREFORE,
 V = 1÷4π€° × lambda × πR ÷ R
V= lambda÷4€°

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