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A half ring of radius R has a charge ofper unit length .The potential at the centre of the half ring is (Assuming potential at infinity is zero and)Possible AnswersSelectedPossible Answer

Rahul Milind Surange , 14 Years ago
Grade 12
anser 1 Answers
Pranav

Last Activity: 6 Years ago

THE TOTAL CHARGE ON THE WHOLE RING IS 
Lambda × the circumference of the ring =
Lambda× 2πR
 
IN CASE OF HALF RING THE CHARGE WILL BE
Lambda × 2πR ÷ 2 = 
Lambda × πR
 
WE KNOW, THE FORMULA FOR POTENTIAL AT A POINT i.e 
V= KQ÷ R
 
WE ALSO KNOW THAT 
Q= LAMBDA × L
(Here for half ring L is πR)
Q= Lambda × πR
 
THEREFORE,
 V = 1÷4π€° × lambda × πR ÷ R
V= lambda÷4€°

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