A half ring of radius R has a charge ofper unit length .The potential at the centre of the half ring is (Assuming potential at infinity is zero and)Possible AnswersSelectedPossible Answer
Rahul Milind Surange , 14 Years ago
Grade 12
1 Answers
Pranav
Last Activity: 6 Years ago
THE TOTAL CHARGE ON THE WHOLE RING IS
Lambda × the circumference of the ring =
Lambda× 2πR
IN CASE OF HALF RING THE CHARGE WILL BE
Lambda × 2πR ÷ 2 =
Lambda × πR
WE KNOW, THE FORMULA FOR POTENTIAL AT A POINT i.e
V= KQ÷ R
WE ALSO KNOW THAT
Q= LAMBDA × L
(Here for half ring L is πR)
Q= Lambda × πR
THEREFORE,
V = 1÷4π€° × lambda × πR ÷ R
V= lambda÷4€°
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