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        1. A projectile is fired with velocity u making angle theta with the horizontal.what is the change in velocity(from initial) when it is at the highest point:-  (A) ucos theta (B) u (C) usin theta (D) (ucos theta - u)
8 months ago

Arun
23381 Points
							The thing to note is when the projectile reaches it's highest point, it has lost all of its vertical velocity.The vertical velocity of this projectile is  usinθ and since the projectile loses this velocity, it would have a difference of  usinθ

8 months ago
Khimraj
3008 Points
							initial velocity = ucos$\Theta \hat{i}$ + usin$\Theta \hat{j}$final velocity = ucos$\Theta \hat{i}$ change in velocity = usin$\Theta$Hope it clears.........................................

8 months ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions