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When r, P and M represent rate of diffusion, pressure and molecular mass, respectively, then the ratio of the rates of diffusion (rA/rB) of two gases A and B, is given as ?

Jayant Kumar , 11 Years ago
Grade 11
anser 2 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

According to Graham's Law of Diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its molecular mass (M) at constant temperature and pressure. Mathematically, this is expressed as:

r ∝ 1/√M

For two gases, A and B, the ratio of their rates of diffusion is given by:

rA / rB = √(MB / MA)

where:

rA and rB are the rates of diffusion of gases A and B, respectively.
MA and MB are the molecular masses of gases A and B, respectively.
If the gases are at different pressures, the modified form of Graham's law states:

rA / rB = √[(PB * MA) / (PA * MB)]

where:

PA and PB are the pressures of gases A and B, respectively.
MA and MB are the molecular masses of gases A and B, respectively.
Thus, the ratio of the rates of diffusion depends on the molecular masses and, if applicable, the pressures of the gases.

Vikas TU

Last Activity: 5 Years ago

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