Saurabh Koranglekar
Last Activity: 5 Years ago
According to Graham's Law of Diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its molecular mass (M) at constant temperature and pressure. Mathematically, this is expressed as:
r ∝ 1/√M
For two gases, A and B, the ratio of their rates of diffusion is given by:
rA / rB = √(MB / MA)
where:
rA and rB are the rates of diffusion of gases A and B, respectively.
MA and MB are the molecular masses of gases A and B, respectively.
If the gases are at different pressures, the modified form of Graham's law states:
rA / rB = √[(PB * MA) / (PA * MB)]
where:
PA and PB are the pressures of gases A and B, respectively.
MA and MB are the molecular masses of gases A and B, respectively.
Thus, the ratio of the rates of diffusion depends on the molecular masses and, if applicable, the pressures of the gases.