The solubility product (K sp ; mol 3 dm –9) of MX 2 at 298 K based on the information available for the given concentration cell is (take 2.303 × R × 298/F = 0.059 V) ?
Jayant Kumar
12 Years agoGrade 11
2 Answers
Saurabh Koranglekar
6 Years ago
Vikas TU
6 Years ago
Dear student Please refer the clear image , The image above does not looks good , it is blurr. Hope for the best Good Luck Cheers
Other Related Questions on engineering entrance exams