The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched by the same force, then the work done is
(a) W2 = W1 (b) W2 = 0.5 W1
(c) W2 = 2W1 (d) W2 = 2W12

Question

Ranjeet Gupta · Answer

Work done is stored in the form of energy So, P.E = W = ½ Kx 2 and here we have to given both the wires are stretched by same force [i.e stretched by same distance] Hence, x is constant for both the wires therefore, W 1 /W 2 = K1/ K 2 W 1 /W 2 = K / 2K …......[ K 1 = K , K 2 =2K] ANS. W 2 = 2W 1

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The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched by the same force, then the work done is (a) W2 = W1 (b) W2 = 0.5 W1 (c) W2 = 2W1 (d) W2 = 2W12

The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched by the same force, then the work done is
(a) W2 = W1 (b) W2 = 0.5 W1
(c) W2 = 2W1 (d) W2 = 2W12

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The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched by the same force, then the work done is (a) W2 = W1 (b) W2 = 0.5 W1 (c) W2 = 2W1 (d) W2 = 2W12

The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched by the same force, then the work done is (a) W2 = W1 (b) W2 = 0.5 W1 (c) W2 = 2W1 (d) W2 = 2W12

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The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched by the same force, then the work done is
(a) W2 = W1 (b) W2 = 0.5 W1
(c) W2 = 2W1 (d) W2 = 2W12