Ranjeet Gupta
Last Activity: 5 Years ago
Work done is stored in the form of energy
So, P.E = W = ½ Kx2
and here we have to given both the wires are stretched by same force [i.e stretched by same distance]
Hence, x is constant for both the wires
therefore, W1/W2 = K1/ K2
W1/W2 = K / 2K …......[ K1= K , K2 =2K]
ANS. W2 = 2W1