The equivalent weight of K2Cr2O7
in acidic medium is expressed in terms of its molecular weight (M) as
A.
M
3
B.
M
4
C.
M
6
D.
M
7

Question

The equivalent weight of K2Cr2O7 in acidic medium is expressed in terms of its molecular weight (M) as A. M 3 B. M 4 C. M 6 D. M 7

Arun · Answer

K2Cr2O7 in solution gives following ions -
K2Cr2O7 + 14H+ + 6e- → 2K+ + 2Cr3+ + 7H2O

Here, 6 e- participate in the reaction, hence chemical equivalent is 6.

Equivalent weight is calculated by -
Z = W / E
Z = 294 / 6
Z = 49 g/mol

Equivalent weight of K2Cr2O7 in acidic medium is 49 g/mol.

hence it willbe M/6

Vikas TU · Answer

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The equivalent weight of K2Cr2O7 in acidic medium is expressed in terms of its molecular weight (M) as A. M 3 B. M 4 C. M 6 D. M 7

The equivalent weight of K2Cr2O7
in acidic medium is expressed in terms of its molecular weight (M) as
A.
M
3
B.
M
4
C.
M
6
D.
M
7

2 Answers

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The equivalent weight of K2Cr2O7 in acidic medium is expressed in terms of its molecular weight (M) as A. M 3 B. M 4 C. M 6 D. M 7

The equivalent weight of K2Cr2O7 in acidic medium is expressed in terms of its molecular weight (M) as A. M 3 B. M 4 C. M 6 D. M 7

2 Answers

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The equivalent weight of K2Cr2O7
in acidic medium is expressed in terms of its molecular weight (M) as
A.
M
3
B.
M
4
C.
M
6
D.
M
7