Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and
x = 8 is

(A)63/2

(B)93/5

(C)105/7

(D)129/10

Question

Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and x = 8 is (A)63/2 (B)93/5 (C)105/7 (D)129/10

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Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and x = 8 is (A)63/2 (B)93/5 (C)105/7 (D)129/10

Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and
x = 8 is

(A)63/2

(B)93/5

(C)105/7

(D)129/10

2 Answers

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Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and x = 8 is (A)63/2 (B)93/5 (C)105/7 (D)129/10

Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and x = 8 is (A)63/2 (B)93/5 (C)105/7 (D)129/10

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Let f(x) = x2/3, x = 0. Then the area of the region enclosed by the c rve y = f(x) and the three lines y = x, x = 1 and
x = 8 is

(A)63/2

(B)93/5

(C)105/7

(D)129/10